4x^2-68x+284=0

Solution for 4x^2-68x+284=0 equation:

4x^2-68x+284=0

a = 4; b = -68; c = +284;
Δ = b2-4ac
Δ = -682-4·4·284
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-4\sqrt{5}}{2*4}=\frac{68-4\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+4\sqrt{5}}{2*4}=\frac{68+4\sqrt{5}}{8}
$